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sample-loader-config.html (1650B)


      1 <!DOCTYPE html>
      2 <html>
      3 <head>
      4 <title>Load MathJax with in-line configuration after the page is ready</title>
      5 <!-- Copyright (c) 2012-2015 The MathJax Consortium -->
      6 <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
      7 <meta http-equiv="X-UA-Compatible" content="IE=edge" />
      8 <meta name="viewport" content="width=device-width, initial-scale=1">
      9 
     10 <script type="text/javascript">
     11 //
     12 //  We wait for the onload function to show that MathJax is laoded after 
     13 //  the page is ready, and then use setTimeout to prove that MathJax is
     14 //  definitely loaded after the page is displayed and active.  MathJax is 
     15 //  loaded two seconds after the page is ready.
     16 //
     17 window.onload = function () {
     18   setTimeout(function () {
     19     var head = document.getElementsByTagName("head")[0], script;
     20     script = document.createElement("script");
     21     script.type = "text/x-mathjax-config";
     22     script[(window.opera ? "innerHTML" : "text")] =
     23       "MathJax.Hub.Config({\n" +
     24       "  tex2jax: { inlineMath: [['$','$'], ['\\\\(','\\\\)']] }\n" +
     25       "});"
     26     head.appendChild(script);
     27     script = document.createElement("script");
     28     script.type = "text/javascript";
     29     script.src  = "../MathJax.js?config=TeX-AMS-MML_HTMLorMML";
     30     head.appendChild(script);
     31   },2000)
     32 }
     33 </script>
     34 
     35 <style>
     36 h1 {
     37   text-align: center;
     38   background: #CCCCCC;
     39   padding: .2em 1em;
     40   border-top: 3px solid #666666;
     41   border-bottom: 3px solid #999999;
     42 }
     43 </style>
     44 
     45 </head>
     46 <body>
     47 
     48 <h1>Adding MathJax with In-Line Configuration</h1>
     49 
     50 <p>
     51 When $a \ne 0$, there are two solutions to $ax^2 + bx + c = 0$ and they are
     52 $$x = {-b \pm \sqrt{b^2-4ac} \over 2a}.$$
     53 </p>
     54 
     55 </body>
     56 </html>